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If 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ N …

 August 11, 2025

Q. If 2tan2x − 5secx − 1 = 0 has 7 different roots in [0, 2nπ],n ∈ N, then greatest value of n is

https://tardigrade.in/question/if-2-tan-2-x-5-sec-x-1-0-has-7-different-roots-in-0-n-pi-2-n-08ftb9lj 

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If 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ N … <body> <h1> Array ( [0] => uf 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [1] => jf 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [2] => kf 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [3] => of 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [4] => 9f 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [5] => 8f 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [6] => id 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [7] => ic 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [8] => iv 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [9] => ig 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [10] => it 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [11] => ir 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [12] => if 1 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [13] => if q tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [14] => if w tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [15] => if 3 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [16] => if 2 ran 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [17] => if 2 fan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [18] => if 2 gan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [19] => if 2 yan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [20] => if 2 6an 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [21] => if 2 5an 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [22] => if 2 tzn 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [23] => if 2 tsn 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [24] => if 2 twn 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [25] => if 2 tqn 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [26] => if 2 tab 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [27] => if 2 tam 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [28] => if 2 taj 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [29] => if 2 tah 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [30] => if 2 tan 1 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [31] => if 2 tan q x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [32] => if 2 tan w x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [33] => if 2 tan 3 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [34] => if 2 tan 2 z-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [35] => if 2 tan 2 c-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [36] => if 2 tan 2 d-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [37] => if 2 tan 2 s-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [38] => if 2 tan 2 x05 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [39] => if 2 tan 2 xp5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [40] => if 2 tan 2 x-4 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [41] => if 2 tan 2 x-r sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [42] => if 2 tan 2 x-t sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [43] => if 2 tan 2 x-6 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [44] => if 2 tan 2 x-5 aec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [45] => if 2 tan 2 x-5 zec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [46] => if 2 tan 2 x-5 xec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [47] => if 2 tan 2 x-5 dec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [48] => if 2 tan 2 x-5 eec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [49] => if 2 tan 2 x-5 wec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [50] => if 2 tan 2 x-5 swc x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [51] => if 2 tan 2 x-5 ssc x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [52] => if 2 tan 2 x-5 sdc x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [53] => if 2 tan 2 x-5 src x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [54] => if 2 tan 2 x-5 s4c x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [55] => if 2 tan 2 x-5 s3c x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [56] => if 2 tan 2 x-5 sex x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [57] => if 2 tan 2 x-5 sev x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [58] => if 2 tan 2 x-5 sef x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [59] => if 2 tan 2 x-5 sed x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [60] => if 2 tan 2 x-5 sec z-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [61] => if 2 tan 2 x-5 sec c-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [62] => if 2 tan 2 x-5 sec d-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [63] => if 2 tan 2 x-5 sec s-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [64] => if 2 tan 2 x-5 sec x01=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [65] => if 2 tan 2 x-5 sec xp1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [66] => if 2 tan 2 x-5 sec x-2=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [67] => if 2 tan 2 x-5 sec x-q=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [68] => if 2 tan 2 x-5 sec x-1=9 has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [69] => if 2 tan 2 x-5 sec x-1=o has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [70] => if 2 tan 2 x-5 sec x-1=p has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [71] => if 2 tan 2 x-5 sec x-1=- has 7 different roots in [0, (n π/2)], n ∈ n &#8230; [72] => if 2 tan 2 x-5 sec x-1=0 gas 7 different roots in [0, (n π/2)], n ∈ n &#8230; [73] => if 2 tan 2 x-5 sec x-1=0 bas 7 different roots in [0, (n π/2)], n ∈ n &#8230; [74] => if 2 tan 2 x-5 sec x-1=0 nas 7 different roots in [0, (n π/2)], n ∈ n &#8230; [75] => if 2 tan 2 x-5 sec x-1=0 jas 7 different roots in [0, (n π/2)], n ∈ n &#8230; [76] => if 2 tan 2 x-5 sec x-1=0 uas 7 different roots in [0, (n π/2)], n ∈ n &#8230; [77] => if 2 tan 2 x-5 sec x-1=0 yas 7 different roots in [0, (n π/2)], n ∈ n &#8230; [78] => if 2 tan 2 x-5 sec x-1=0 hzs 7 different roots in [0, (n π/2)], n ∈ n &#8230; [79] => if 2 tan 2 x-5 sec x-1=0 hss 7 different roots in [0, (n π/2)], n ∈ n &#8230; [80] => if 2 tan 2 x-5 sec x-1=0 hws 7 different roots in [0, (n π/2)], n ∈ n &#8230; [81] => if 2 tan 2 x-5 sec x-1=0 hqs 7 different roots in [0, (n π/2)], n ∈ n &#8230; [82] => if 2 tan 2 x-5 sec x-1=0 haa 7 different roots in [0, (n π/2)], n ∈ n &#8230; [83] => if 2 tan 2 x-5 sec x-1=0 haz 7 different roots in [0, (n π/2)], n ∈ n &#8230; [84] => if 2 tan 2 x-5 sec x-1=0 hax 7 different roots in [0, (n π/2)], n ∈ n &#8230; [85] => if 2 tan 2 x-5 sec x-1=0 had 7 different roots in [0, (n π/2)], n ∈ n &#8230; [86] => if 2 tan 2 x-5 sec x-1=0 hae 7 different roots in [0, (n π/2)], n ∈ n &#8230; [87] => if 2 tan 2 x-5 sec x-1=0 haw 7 different roots in [0, (n π/2)], n ∈ n &#8230; [88] => if 2 tan 2 x-5 sec x-1=0 has 6 different roots in [0, (n π/2)], n ∈ n &#8230; [89] => if 2 tan 2 x-5 sec x-1=0 has y different roots in [0, (n π/2)], n ∈ n &#8230; [90] => if 2 tan 2 x-5 sec x-1=0 has u different roots in [0, (n π/2)], n ∈ n &#8230; [91] => if 2 tan 2 x-5 sec x-1=0 has 8 different roots in [0, (n π/2)], n ∈ n &#8230; [92] => if 2 tan 2 x-5 sec x-1=0 has 7 sifferent roots in [0, (n π/2)], n ∈ n &#8230; [93] => if 2 tan 2 x-5 sec x-1=0 has 7 xifferent roots in [0, (n π/2)], n ∈ n &#8230; [94] => if 2 tan 2 x-5 sec x-1=0 has 7 cifferent roots in [0, (n π/2)], n ∈ n &#8230; [95] => if 2 tan 2 x-5 sec x-1=0 has 7 fifferent roots in [0, (n π/2)], n ∈ n &#8230; [96] => if 2 tan 2 x-5 sec x-1=0 has 7 rifferent roots in [0, (n π/2)], n ∈ n &#8230; [97] => if 2 tan 2 x-5 sec x-1=0 has 7 eifferent roots in [0, (n π/2)], n ∈ n &#8230; [98] => if 2 tan 2 x-5 sec x-1=0 has 7 dufferent roots in [0, (n π/2)], n ∈ n &#8230; [99] => if 2 tan 2 x-5 sec x-1=0 has 7 djfferent roots in [0, (n π/2)], n ∈ n &#8230; [100] => if 2 tan 2 x-5 sec x-1=0 has 7 dkfferent roots in [0, (n π/2)], n ∈ n &#8230; [101] => if 2 tan 2 x-5 sec x-1=0 has 7 dofferent roots in [0, (n π/2)], n ∈ n &#8230; [102] => if 2 tan 2 x-5 sec x-1=0 has 7 d9fferent roots in [0, (n π/2)], n ∈ n &#8230; [103] => if 2 tan 2 x-5 sec x-1=0 has 7 d8fferent roots in [0, (n π/2)], n ∈ n &#8230; [104] => if 2 tan 2 x-5 sec x-1=0 has 7 didferent roots in [0, (n π/2)], n ∈ n &#8230; [105] => if 2 tan 2 x-5 sec x-1=0 has 7 dicferent roots in [0, (n π/2)], n ∈ n &#8230; [106] => if 2 tan 2 x-5 sec x-1=0 has 7 divferent roots in [0, (n π/2)], n ∈ n &#8230; [107] => if 2 tan 2 x-5 sec x-1=0 has 7 digferent roots in [0, (n π/2)], n ∈ n &#8230; [108] => if 2 tan 2 x-5 sec x-1=0 has 7 ditferent roots in [0, (n π/2)], n ∈ n &#8230; [109] => if 2 tan 2 x-5 sec x-1=0 has 7 dirferent roots in [0, (n π/2)], n ∈ n &#8230; [110] => if 2 tan 2 x-5 sec x-1=0 has 7 difderent roots in [0, (n π/2)], n ∈ n &#8230; [111] => if 2 tan 2 x-5 sec x-1=0 has 7 difcerent roots in [0, (n π/2)], n ∈ n &#8230; [112] => if 2 tan 2 x-5 sec x-1=0 has 7 difverent roots in [0, (n π/2)], n ∈ n &#8230; [113] => if 2 tan 2 x-5 sec x-1=0 has 7 difgerent roots in [0, (n π/2)], n ∈ n &#8230; [114] => if 2 tan 2 x-5 sec x-1=0 has 7 difterent roots in [0, (n π/2)], n ∈ n &#8230; [115] => if 2 tan 2 x-5 sec x-1=0 has 7 difrerent roots in [0, (n π/2)], n ∈ n &#8230; [116] => if 2 tan 2 x-5 sec x-1=0 has 7 diffwrent roots in [0, (n π/2)], n ∈ n &#8230; [117] => if 2 tan 2 x-5 sec x-1=0 has 7 diffsrent roots in [0, (n π/2)], n ∈ n &#8230; [118] => if 2 tan 2 x-5 sec x-1=0 has 7 diffdrent roots in [0, (n π/2)], n ∈ n &#8230; [119] => if 2 tan 2 x-5 sec x-1=0 has 7 diffrrent roots in [0, (n π/2)], n ∈ n &#8230; [120] => if 2 tan 2 x-5 sec x-1=0 has 7 diff4rent roots in [0, (n π/2)], n ∈ n &#8230; [121] => if 2 tan 2 x-5 sec x-1=0 has 7 diff3rent roots in [0, (n π/2)], n ∈ n &#8230; [122] => if 2 tan 2 x-5 sec x-1=0 has 7 diffeeent roots in [0, (n π/2)], n ∈ n &#8230; [123] => if 2 tan 2 x-5 sec x-1=0 has 7 diffedent roots in [0, (n π/2)], n ∈ n &#8230; [124] => if 2 tan 2 x-5 sec x-1=0 has 7 diffefent roots in [0, (n π/2)], n ∈ n &#8230; [125] => if 2 tan 2 x-5 sec x-1=0 has 7 diffetent roots in [0, (n π/2)], n ∈ n &#8230; [126] => if 2 tan 2 x-5 sec x-1=0 has 7 diffe5ent roots in [0, (n π/2)], n ∈ n &#8230; [127] => if 2 tan 2 x-5 sec x-1=0 has 7 diffe4ent roots in [0, (n π/2)], n ∈ n &#8230; [128] => if 2 tan 2 x-5 sec x-1=0 has 7 differwnt roots in [0, (n π/2)], n ∈ n &#8230; [129] => if 2 tan 2 x-5 sec x-1=0 has 7 differsnt roots in [0, (n π/2)], n ∈ n &#8230; [130] => if 2 tan 2 x-5 sec x-1=0 has 7 differdnt roots in [0, (n π/2)], n ∈ n &#8230; [131] => if 2 tan 2 x-5 sec x-1=0 has 7 differrnt roots in [0, (n π/2)], n ∈ n &#8230; [132] => if 2 tan 2 x-5 sec x-1=0 has 7 differ4nt roots in [0, (n π/2)], n ∈ n &#8230; [133] => if 2 tan 2 x-5 sec x-1=0 has 7 differ3nt roots in [0, (n π/2)], n ∈ n &#8230; [134] => if 2 tan 2 x-5 sec x-1=0 has 7 differebt roots in [0, (n π/2)], n ∈ n &#8230; [135] => if 2 tan 2 x-5 sec x-1=0 has 7 differemt roots in [0, (n π/2)], n ∈ n &#8230; [136] => if 2 tan 2 x-5 sec x-1=0 has 7 differejt roots in [0, (n π/2)], n ∈ n &#8230; [137] => if 2 tan 2 x-5 sec x-1=0 has 7 differeht roots in [0, (n π/2)], n ∈ n &#8230; [138] => if 2 tan 2 x-5 sec x-1=0 has 7 differenr roots in [0, (n π/2)], n ∈ n &#8230; [139] => if 2 tan 2 x-5 sec x-1=0 has 7 differenf roots in [0, (n π/2)], n ∈ n &#8230; [140] => if 2 tan 2 x-5 sec x-1=0 has 7 differeng roots in [0, (n π/2)], n ∈ n &#8230; [141] => if 2 tan 2 x-5 sec x-1=0 has 7 differeny roots in [0, (n π/2)], n ∈ n &#8230; [142] => if 2 tan 2 x-5 sec x-1=0 has 7 differen6 roots in [0, (n π/2)], n ∈ n &#8230; [143] => if 2 tan 2 x-5 sec x-1=0 has 7 differen5 roots in [0, (n π/2)], n ∈ n &#8230; [144] => if 2 tan 2 x-5 sec x-1=0 has 7 different eoots in [0, (n π/2)], n ∈ n &#8230; [145] => if 2 tan 2 x-5 sec x-1=0 has 7 different doots in [0, (n π/2)], n ∈ n &#8230; [146] => if 2 tan 2 x-5 sec x-1=0 has 7 different foots in [0, (n π/2)], n ∈ n &#8230; [147] => if 2 tan 2 x-5 sec x-1=0 has 7 different toots in [0, (n π/2)], n ∈ n &#8230; [148] => if 2 tan 2 x-5 sec x-1=0 has 7 different 5oots in [0, (n π/2)], n ∈ n &#8230; [149] => if 2 tan 2 x-5 sec x-1=0 has 7 different 4oots in [0, (n π/2)], n ∈ n &#8230; [150] => if 2 tan 2 x-5 sec x-1=0 has 7 different riots in [0, (n π/2)], n ∈ n &#8230; [151] => if 2 tan 2 x-5 sec x-1=0 has 7 different rkots in [0, (n π/2)], n ∈ n &#8230; [152] => if 2 tan 2 x-5 sec x-1=0 has 7 different rlots in [0, (n π/2)], n ∈ n &#8230; [153] => if 2 tan 2 x-5 sec x-1=0 has 7 different rpots in [0, (n π/2)], n ∈ n &#8230; [154] => if 2 tan 2 x-5 sec x-1=0 has 7 different r0ots in [0, (n π/2)], n ∈ n &#8230; [155] => if 2 tan 2 x-5 sec x-1=0 has 7 different r9ots in [0, (n π/2)], n ∈ n &#8230; [156] => if 2 tan 2 x-5 sec x-1=0 has 7 different roits in [0, (n π/2)], n ∈ n &#8230; [157] => if 2 tan 2 x-5 sec x-1=0 has 7 different rokts in [0, (n π/2)], n ∈ n &#8230; [158] => if 2 tan 2 x-5 sec x-1=0 has 7 different rolts in [0, (n π/2)], n ∈ n &#8230; [159] => if 2 tan 2 x-5 sec x-1=0 has 7 different ropts in [0, (n π/2)], n ∈ n &#8230; [160] => if 2 tan 2 x-5 sec x-1=0 has 7 different ro0ts in [0, (n π/2)], n ∈ n &#8230; [161] => if 2 tan 2 x-5 sec x-1=0 has 7 different ro9ts in [0, (n π/2)], n ∈ n &#8230; [162] => if 2 tan 2 x-5 sec x-1=0 has 7 different roors in [0, (n π/2)], n ∈ n &#8230; [163] => if 2 tan 2 x-5 sec x-1=0 has 7 different roofs in [0, (n π/2)], n ∈ n &#8230; [164] => if 2 tan 2 x-5 sec x-1=0 has 7 different roogs in [0, (n π/2)], n ∈ n &#8230; [165] => if 2 tan 2 x-5 sec x-1=0 has 7 different rooys in [0, (n π/2)], n ∈ n &#8230; [166] => if 2 tan 2 x-5 sec x-1=0 has 7 different roo6s in [0, (n π/2)], n ∈ n &#8230; [167] => if 2 tan 2 x-5 sec x-1=0 has 7 different roo5s in [0, (n π/2)], n ∈ n &#8230; [168] => if 2 tan 2 x-5 sec x-1=0 has 7 different roota in [0, (n π/2)], n ∈ n &#8230; [169] => if 2 tan 2 x-5 sec x-1=0 has 7 different rootz in [0, (n π/2)], n ∈ n &#8230; [170] => if 2 tan 2 x-5 sec x-1=0 has 7 different rootx in [0, (n π/2)], n ∈ n &#8230; [171] => if 2 tan 2 x-5 sec x-1=0 has 7 different rootd in [0, (n π/2)], n ∈ n &#8230; [172] => if 2 tan 2 x-5 sec x-1=0 has 7 different roote in [0, (n π/2)], n ∈ n &#8230; [173] => if 2 tan 2 x-5 sec x-1=0 has 7 different rootw in [0, (n π/2)], n ∈ n &#8230; [174] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots un [0, (n π/2)], n ∈ n &#8230; [175] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots jn [0, (n π/2)], n ∈ n &#8230; [176] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots kn [0, (n π/2)], n ∈ n &#8230; [177] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots on [0, (n π/2)], n ∈ n &#8230; [178] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots 9n [0, (n π/2)], n ∈ n &#8230; [179] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots 8n [0, (n π/2)], n ∈ n &#8230; [180] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots ib [0, (n π/2)], n ∈ n &#8230; [181] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots im [0, (n π/2)], n ∈ n &#8230; [182] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots ij [0, (n π/2)], n ∈ n &#8230; [183] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots ih [0, (n π/2)], n ∈ n &#8230; [184] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [9, (n π/2)], n ∈ n &#8230; [185] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [o, (n π/2)], n ∈ n &#8230; [186] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [p, (n π/2)], n ∈ n &#8230; [187] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [-, (n π/2)], n ∈ n &#8230; [188] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0m (n π/2)], n ∈ n &#8230; [189] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0k (n π/2)], n ∈ n &#8230; [190] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0l (n π/2)], n ∈ n &#8230; [191] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0. (n π/2)], n ∈ n &#8230; [192] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0 (n π/2)], n ∈ n &#8230; [193] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (b π/2)], n ∈ n &#8230; [194] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (m π/2)], n ∈ n &#8230; [195] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (j π/2)], n ∈ n &#8230; [196] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (h π/2)], n ∈ n &#8230; [197] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/1)], n ∈ n &#8230; [198] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/q)], n ∈ n &#8230; [199] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/w)], n ∈ n &#8230; [200] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/3)], n ∈ n &#8230; [201] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)]m n ∈ n &#8230; [202] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)]k n ∈ n &#8230; [203] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)]l n ∈ n &#8230; [204] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)]. n ∈ n &#8230; [205] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)] n ∈ n &#8230; [206] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], b ∈ n &#8230; [207] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], m ∈ n &#8230; [208] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], j ∈ n &#8230; [209] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], h ∈ n &#8230; [210] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ b &#8230; [211] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ m &#8230; [212] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ j &#8230; [213] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ h &#8230; [214] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#7230; [215] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#u230; [216] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#i230; [217] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#9230; [218] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8130; [219] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8q30; [220] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8w30; [221] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8330; [222] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8220; [223] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#82w0; [224] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#82e0; [225] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8240; [226] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#8239; [227] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#823o; [228] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#823p; [229] => if 2 tan 2 x-5 sec x-1=0 has 7 different roots in [0, (n π/2)], n ∈ n &#823-; ) https://clipperroutesevere.com/kdjbw4ywu?key=a54852e5dee5f9fa314d768d692142d1 </h1> </body>